x^2+32x-12=0

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Solution for x^2+32x-12=0 equation:


Simplifying
x2 + 32x + -12 = 0

Reorder the terms:
-12 + 32x + x2 = 0

Solving
-12 + 32x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '12' to each side of the equation.
-12 + 32x + 12 + x2 = 0 + 12

Reorder the terms:
-12 + 12 + 32x + x2 = 0 + 12

Combine like terms: -12 + 12 = 0
0 + 32x + x2 = 0 + 12
32x + x2 = 0 + 12

Combine like terms: 0 + 12 = 12
32x + x2 = 12

The x term is 32x.  Take half its coefficient (16).
Square it (256) and add it to both sides.

Add '256' to each side of the equation.
32x + 256 + x2 = 12 + 256

Reorder the terms:
256 + 32x + x2 = 12 + 256

Combine like terms: 12 + 256 = 268
256 + 32x + x2 = 268

Factor a perfect square on the left side:
(x + 16)(x + 16) = 268

Calculate the square root of the right side: 16.370705544

Break this problem into two subproblems by setting 
(x + 16) equal to 16.370705544 and -16.370705544.

Subproblem 1

x + 16 = 16.370705544 Simplifying x + 16 = 16.370705544 Reorder the terms: 16 + x = 16.370705544 Solving 16 + x = 16.370705544 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + x = 16.370705544 + -16 Combine like terms: 16 + -16 = 0 0 + x = 16.370705544 + -16 x = 16.370705544 + -16 Combine like terms: 16.370705544 + -16 = 0.370705544 x = 0.370705544 Simplifying x = 0.370705544

Subproblem 2

x + 16 = -16.370705544 Simplifying x + 16 = -16.370705544 Reorder the terms: 16 + x = -16.370705544 Solving 16 + x = -16.370705544 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-16' to each side of the equation. 16 + -16 + x = -16.370705544 + -16 Combine like terms: 16 + -16 = 0 0 + x = -16.370705544 + -16 x = -16.370705544 + -16 Combine like terms: -16.370705544 + -16 = -32.370705544 x = -32.370705544 Simplifying x = -32.370705544

Solution

The solution to the problem is based on the solutions from the subproblems. x = {0.370705544, -32.370705544}

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